Grasshopper Chess: Helpstalemates

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Helpstalemate in 2

4 men

A. Kniest
Problemist Fairy Chess Supplement #832 June 1933
Helpstalemate in 2, with set play

Solution: set 1....Pc8=Q. play 1.Gd8 Pc8=Q 2.Gb8 Qc6.

Comments: Exact Echo. The original had no WK.

5 men

A. Kniest
Problemist Fairy Chess Supplement #1015 October 1933
Helpstalemate in 2, (b) Rd1 to g4

Solution: (a) 1.Ka5 Ge1 2.Pb5 Rd4.
(b) 1.Ka5 Gb8 2.Pb5 Rb4.

Comments: Change of function for the G.

8 men

C. M. Fox
Problemist Fairy Chess Supplement #350 February 1932
Helpstalemate in 2, (b) Ge8 to d7

Solution: (a) 1.Qe5 P×e5 2.P×e5 Se3.
(b) 1.K×d5 Sd8 2.Qd3 K×d3.

Comments: Two different single-file finales.


Helpstalemate in 3

6 men

J. de A. Almay
Problemist Fairy Chess Supplement #49 October 1930
Helpstalemate in 3

Solution: 1.Ka1 Kg8 2.Ga2 Ph7 3.Pb1=G Ph8=G stalemate

Comments: Epaulette formation. 1....Kg6 allows 4.Gh7

7 men

C. M. Fox
Problemist Fairy Chess Supplement #269 October 1931
Helpstalemate in 3, (b) remove Ge3

Solution:
(a) 1.Gc1 Gd4 2.Gb3 Kb4 3.Ga3 K×Ga3 stalemate
(b) 1.Gc2 Gd4 2.Rb2 Kd2 3.Ra2 Kc1 stalemate

Comments: Exact echo. Antipin of R.

8 men

C. M. Fox
Problemist Fairy Chess Supplement #51 October 1930
Helpstalemate in 3, (b) Pd5 to c5

Solution:
(a) 1.Pd4 Bg7 2.Rh8 Kc6 3.Gh7 B×d4 stalemate
(b) 1.Ra1 Bb2 2.Gb1 Ba3 3.Ga2 B×c5 stalemate

Comments: Trapped rook. Echoes, including with the diagram position. Epaulettes.

P. C. Taylor
Problemist Fairy Chess Supplement #464 June 1932
Helpstalemate in 3, (b) Gf6 to d4

Solution:
(a) 1.000 Gf5 2.Re8 Nd7† 3.Re6† Gd6 stalemate
(b) 1.Kd8 Gf6 2.Ra6† G×Ra6 3.Kc8 Sc6 stalemate

Comments: Rook pinned in first line and captured in second. Pin and antipin.

9 men

C.M.Fox
Problemist Fairy Chess Supplement 1935
Helpstalemate in 3 with set play

Solution:
1....Gb6 2.Gd7 G×c7 3.Gb7 Gb×b7 stalemate.
1.Na6 Ga5 2.Na7 Gb8† 3.Nc8 Ga7 stalemate. (Ns pinned)

Comment: Both finales symmetric, but quite different.

9 men

C. M. Fox
Problemist Fairy Chess Supplement #976 October 1933
Helpstalemate in 3

Solution: 1.Gc6 Kf7 2.Gg8 Kg6 3.Gh6 K×Gh6 stalemate

Comments: Stranding the six remaining grasshoppers

11 men

P. C. Taylor
Problemist Fairy Chess Supplement #976 October 1933
Helpstalemate in 3

Solution: 1.Gd3 Ba4 2.Gf1 Bd1 3.P×d1=G Re8 stalemate

Comments: Asymmetry. Epaulettes. Bishop sacrifice. Promotion to G.
Described by solvers as "charming".

13 men

P. C. Taylor
Problemist Fairy Chess Supplement #267 October 1931
Helpstalemate in 3

Solution: 1.Sb7 Gb5 2.Gd8 Ga8 3.Kd5 Se4 stalemate

Comments: Remarkable final position. Pin and antipins.
Much traffic on stalemate square d5.


Helpstalemate in 4

7 men 2 types (KG)

C. M. Fox
PFCS Aug 1932 (523)
Helpstalemate in 4

Solution: A solution is: 1.Kf5 Kf7 2.Kg5 Gf6 3.Kh6 Gg6+ 4.Kh7 Gg7= stalemate Unsound.

Comments: But in this Gg1 and Gg8 are not needed.

7 men 2 types (KG)

C. M. Fox
PFCS Apr 1933 (732)
Helpstalemate in 4

Solution: 1.Gd8 Kc7 2.Gb8 Kb6 3.Kd7 Kxc5 4.Kc8 Kc6 stalemate.

Comments: WK "spiral journey". Epaulette formation. Two other BGs stalemated by isolation.

7 men 3 types (KGP)

T. R. Dawson and C. M. Fox
PFCS AAug 1932 (522)
Helpstalemate in 4, (b) d6-a3

Solution: 1. ?? stalemate Not Noted

Comments: ??

9 men 2 types (KG)

C. M. Fox
PFCS Oct 1931 (268)
Helpstalemate in 4

Solution: 1. stalemate Not Noted

Comments:

9 men 2 types (KG)

C. M. Fox
PFCS Dec 1932 (610)
Helpstalemate in 4

Solution: Intended: 1.Ge6 Kxf5 2.Gd5 Kxe6 3.Gc5 Kf7 4.Gdg8 Kxf8 stalemate

Comments: But dual and cook: 1.Ge5 Kxe5 2.Gf4 Kxf5 3.Gf6 Kg6 4.Gh6 Kxh6 stalemate.

14 men 4 types (KRNG)

J. A. Lewis
PFCS Dec 1933 (1042)
Helpstalemate in 4

Solution: 1.Gh3 Ge1 2.Gc6 Rc3 3.Sb3 Gb4+ 4.Sa1 Gfe2 stalemate

Comments: interposition checks


Helpstalemate in 5

3 men

K. Hannemann
Probleemblad 1963
Helpstalemate in 5, b) Gd7, c) Gg6

Solution: a) 1.Kc4 Ke4 2.Kb3 Kd3 3.Kb2 Kc4 4.Gb1 Kb4 5.Ka1 Ka3 stalemate
b) 1.Kc6 Ke2 2.Gb5 Kd3 3.Kb7 Kc4 4.Gb8 Kb5 5.Ka8 Ka6 stalemate
c) 1.Ke4 Kg2 2.Gg1 Kh3 3.Kf3 Kh4 4.Kg2 Kg4 5.Kh1 Kh3 stalemate

Comments: Ideal stalemate. Exact echoes.

8 men

H. Rossler
Feenschach 1975
Helpstalemate in 5

Solution: 1.g6 b8=G 2.Gg7 Gb1 3.g5 Gg6 4.b1=G Gg8 5.Gg6 fxg6 stalemate

Comments: Interchange of BG and BP.

13 men

K. Gandew
Caissa's Fröliche Tiefgarage 1971 (29)
Helpstalemate in 5

Solution: 1.Qa8 bxa8=Q 2.Rb8 axb8=R 3.Gc8 dxc8=B 4.Rd8 exd8=S 5.g1=G Sxf7 stalemate

Comments: All the promotions. "Allumwandlung".


Helpstalemate in 6 or more

7 men

E. D.Kelly
Feenschach 1974
Helpstalemate in 6

Solution: 1.Ka7 Kf7 2.Kb6 Ga7 3.Gf8 Gc5 4.Gb4 Gxa3 5.Ka5 Ga6 6.b6 Gc6 stalemate

10 men

F. S. Bondarenko
Feenschach 1960 (4736)
Helpstalemate in 9

Solution: 1.Bd7 Kb3 2.Kh1 Ka2 3.Ga1 Kb2 4.Gb1 Kc2 5.Gcc1 Kd2 6.Gdd1 Ke2
7.Gee1 Kf2 8.Gff1 Kg3 9.Bh3 Kxh3 stalemate

Comments: Lone WK. Line-up along rank.

11 men

C. M. Fox
PFCS Jun 1932 (474)
Helpstalemate in 7½

Solution: 1... Sb4 2.Ge4 Sc6 3.Gb7 Sd4 4.Gd5 Se2 5.Gf3 Sg3 6.Gg2 Sf5 7.Ge4 Sd6 8.Gc6 Sc8 stalemate

Comments: Diagonal line-up. Unlike the following example this has one BG already on the diagonal.

12 men

C. M. Fox
PFCS Jun 1932 (475)
Helpstalemate in 7½

Solution: 1... Bf2 2.Gg2 Be3 3.Ge4 Bg1 4.Gh1 Bc5 5.Gc6 Bd6 6.Gd5 Bc7 7.Gb7 Bf4 8.Gf3 Bb8 stalemate

Comments: Diagonal line-up.

15 men

P. A. Petkow
Feenschach 1960 (5024)
Helpstalemate in 8

Solution: 1.Ra8 h3 2.R5a7 hxg4 3.Qa6 g5 4.Ka5 g6 5.Gb4 g7 6.G4b6 g8=G 7.Geb4 Gb3 8.cxb3+ Ka3 stalemate

Comments: Excelsior.

16 men

G. J. Sontag
Fairy Chess Review 1954 (9997)
Helpstalemate in 8

Solution: 1.Sg3 Kxg3 2.Rh4+ Kxf3 3.Bg3 Kxg3 4.f4+ Kxh4 5.Rg5 Kxg5 6.b5 Kxf4 7.Ge3 Kxe3 8.Gf2 Kxf2 stalemate

Comments: WK circuit. Minimal White force.


BLANK

Composer
Source Problem number and date
Helpstalemate in

Solution: 1. stalemate

Comments: