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A. Kniest
Solution: set 1....Pc8=Q. play 1.Gd8 Pc8=Q 2.Gb8 Qc6. Comments: Exact Echo. The original had no WK. |
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A. Kniest
Solution: (a) 1.Ka5 Ge1 2.Pb5 Rd4.
Comments: Change of function for the G. |
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C. M. Fox
Solution: (a) 1.Qe5 P×e5 2.P×e5 Se3.
Comments: Two different single-file finales. |
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J. de A. Almay
Solution: 1.Ka1 Kg8 2.Ga2 Ph7 3.Pb1=G Ph8=G stalemate Comments: Epaulette formation. 1....Kg6 allows 4.Gh7 |
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C. M. Fox
Solution:
Comments: Exact echo. Antipin of R. |
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C. M. Fox
Solution:
Comments: Trapped rook. Echoes, including with the diagram position. Epaulettes. |
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P. C. Taylor
Solution:
Comments: Rook pinned in first line and captured in second. Pin and antipin. |
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C.M.Fox
Solution:
Comment: Both finales symmetric, but quite different. |
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C. M. Fox
Solution: 1.Gc6 Kf7 2.Gg8 Kg6 3.Gh6 K×Gh6 stalemate Comments: Stranding the six remaining grasshoppers |
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P. C. Taylor
Solution: 1.Gd3 Ba4 2.Gf1 Bd1 3.P×d1=G Re8 stalemate Comments: Asymmetry. Epaulettes. Bishop sacrifice. Promotion to G.
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P. C. Taylor
Solution: 1.Sb7 Gb5 2.Gd8 Ga8 3.Kd5 Se4 stalemate Comments: Remarkable final position. Pin and antipins.
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C. M. Fox
Solution: A solution is: 1.Kf5 Kf7 2.Kg5 Gf6 3.Kh6 Gg6+ 4.Kh7 Gg7= stalemate Unsound. Comments: But in this Gg1 and Gg8 are not needed. |
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C. M. Fox
Solution: 1.Gd8 Kc7 2.Gb8 Kb6 3.Kd7 Kxc5 4.Kc8 Kc6 stalemate. Comments: WK "spiral journey". Epaulette formation. Two other BGs stalemated by isolation. |
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T. R. Dawson and C. M. Fox
Solution: 1. ?? stalemate Not Noted Comments: ?? |
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C. M. Fox
Solution: 1. stalemate Not Noted Comments: |
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C. M. Fox
Solution: Intended: 1.Ge6 Kxf5 2.Gd5 Kxe6 3.Gc5 Kf7 4.Gdg8 Kxf8 stalemate Comments: But dual and cook: 1.Ge5 Kxe5 2.Gf4 Kxf5 3.Gf6 Kg6 4.Gh6 Kxh6 stalemate. |
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J. A. Lewis
Solution: 1.Gh3 Ge1 2.Gc6 Rc3 3.Sb3 Gb4+ 4.Sa1 Gfe2 stalemate Comments: interposition checks |
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K. Hannemann
Solution: a) 1.Kc4 Ke4 2.Kb3 Kd3 3.Kb2 Kc4 4.Gb1 Kb4 5.Ka1 Ka3 stalemate
Comments: Ideal stalemate. Exact echoes. |
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H. Rossler
Solution: 1.g6 b8=G 2.Gg7 Gb1 3.g5 Gg6 4.b1=G Gg8 5.Gg6 fxg6 stalemate Comments: Interchange of BG and BP. |
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K. Gandew
Solution: 1.Qa8 bxa8=Q 2.Rb8 axb8=R 3.Gc8 dxc8=B 4.Rd8 exd8=S 5.g1=G Sxf7 stalemate Comments: All the promotions. "Allumwandlung". |
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E. D.Kelly
Solution: 1.Ka7 Kf7 2.Kb6 Ga7 3.Gf8 Gc5 4.Gb4 Gxa3 5.Ka5 Ga6 6.b6 Gc6 stalemate |
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F. S. Bondarenko
Solution: 1.Bd7 Kb3 2.Kh1 Ka2 3.Ga1 Kb2 4.Gb1 Kc2 5.Gcc1 Kd2 6.Gdd1 Ke2
Comments: Lone WK. Line-up along rank. |
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C. M. Fox
Solution: 1... Sb4 2.Ge4 Sc6 3.Gb7 Sd4 4.Gd5 Se2 5.Gf3 Sg3 6.Gg2 Sf5 7.Ge4 Sd6 8.Gc6 Sc8 stalemate Comments: Diagonal line-up. Unlike the following example this has one BG already on the diagonal. |
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C. M. Fox
Solution: 1... Bf2 2.Gg2 Be3 3.Ge4 Bg1 4.Gh1 Bc5 5.Gc6 Bd6 6.Gd5 Bc7 7.Gb7 Bf4 8.Gf3 Bb8 stalemate Comments: Diagonal line-up. |
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P. A. Petkow
Solution: 1.Ra8 h3 2.R5a7 hxg4 3.Qa6 g5 4.Ka5 g6 5.Gb4 g7 6.G4b6 g8=G 7.Geb4 Gb3 8.cxb3+ Ka3 stalemate Comments: Excelsior. |
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G. J. Sontag
Solution: 1.Sg3 Kxg3 2.Rh4+ Kxf3 3.Bg3 Kxg3 4.f4+ Kxh4 5.Rg5 Kxg5 6.b5 Kxf4 7.Ge3 Kxe3 8.Gf2 Kxf2 stalemate Comments: WK circuit. Minimal White force. |
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Composer
Solution: 1. stalemate Comments: |