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5 men 3 types
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A. H. Kniest
Solution: 1.Se5 Kh8 2.Gd5 Kg8 3.Sf7 Comments: Asymmetry, switchback. |
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A. Kniest
Solution: 1.Kc3 Gb1/a2 2.Rb8/h2 Ka2/b1 3.Ra8/h1 Comments: Symmetry |
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W. Kramer
Solution: set 1....Ge2 2.Gf1 Gg2 3.Gh3
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W. E. Lester
Solution: 1.Gb2 unstalemating Kb8 2.Bb6 Ka8 3.Rc8 |
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T. R. Dawson
Solution:
Comments: Last move P(x)h8=G. As published, with Gh8 at g7 for 1.Rh3, the position was illegal. |
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T. R. Dawson
Solution:
Comments: Changed play. Irreversible G-move in set play. Stranded G in actual play. |
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G. Bernecker
Solution: 1.Pg3 Gb7 2.Gg4 Gd7 3.Gc8 Comments: Rudimentary |
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H. Hultberg
Solution:
Comments: Changed promotion. |
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H. Hultberg
Solution:
Comments: Underpromotion to avoid stalemate. |
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J. Manskopf
Solution: 1.Bg7 Gh8 2.Ba1 Gb8 3.PxGb8=Q/R Comments: B and G interchange. White shepherds G to required destination. |
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Miss D. D'Sylva
Solution:
Comments: BG bystander in second mate. |
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H. Hultberg
Solution: Set: 1... Ka8 2.g8=Q+ Ka7 3.Qb8
Comments: Why Gh5? |
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H. Hultberg
Solution: Set 1... Gd8 2.cxd8=S Gc8/Gh6 3.Sf7
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C. Eckherdt
Solution: 1.Ge8 1... e3 2.Ge2 g4 3.Gh5 1... g4 2.Ge3 g3 3.Gh3 Comments: G over P routes. BG stranded. |
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W. E. Lester
Solution: 1.Qc7 (waiting move) Gc6 2.dxc6 g2 3.Qb7 Comments: Incidental G. |
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E & P. H. Torngren
Solution: 1.Ga7 Gb1/Gf3 2.Rb7 any 3.Gc7
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H. Hultberg & P. H. Torngren (independently)
Solution: Set 1... Gh6 2.h8=B any 3.Bf6 Play: 1.Rg5 Gh6 2.h8=S any 3.Sg6 Comments: With Rg5 the set and actual play reverse. |
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H. Hultberg
Solution: Set: 1... Ga7 2.b8=S 1... Ka7 2.b8=Q+ Ka6 3.Qa8(etc)
Comments: G incidental |
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T. R. Dawson
Solution: 1.Gf1 1... Kg1/Kh1 2.Gf4+ Kh2 3.Gf2 1... h3 2.g3 h4/Kg1/Kh1 3.Gf4 Comments: Set Stalemate |
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H. Hultberg
Solution: Set: 1... Gh6 2.h8=B Gh1 3.Be5 1... Gb8 2.h8+Q/R
Comments: Change of promotion. |
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T. R. Dawson
Solution: 1.Ge7 1... Kb8 2.Bc6 Ka7/c8 3.Bb7 1... Ka7 2.Bc8 Kb8/a8 3.Bb7 Comments: Same White formation in all mates, BK position varies. |
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O. Dankert
Solution: 1.Ba2 Gd8 2.Kf8 Gg8 3.Ke7 Comments: WK switchback, G over G mate.
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H. Hultberg
Solution: Set: 1... Gh6 2.h8=G Gh2 3.Gc3 1... Gc3 2.h8=Q/R
Comments: Changed mate. |
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H. Hultberg
Solution: Set: 1... Gb8 2.cxb8=B Ga8/Gh5 3.Bf6 1... Gh5/Gb5 2.c8=Q/R
Comments: Not cxb8=Q stalemate. |
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P. H. Torngren
Solution: Set: 1...Gh6 2.h8=G Gh1 3.Gb8 1... Gb8 2.h8=Q/R
Comments: |
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T. R. Dawson
Solution: 1.Be7 1... Kb8 2.Bd6+ Ka7 3.Gd7 1... Gd8/Gc5/Gd2 2.B(x)c5+ Kb8 3.Gb5 Comments: |
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H. Hultberg
Solution: Set: 1... Gh6 2.h8=S Gf4/Gh3 3.Sg6 Play: 1.g6 Gh6 2.h8=B Gf6/Gh3 3.B(x)f6 Comments: Changed promotion. |
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H. Hultberg
Solution: Set: 1... Gh6 2.h8=Q Gxh2 3.Qa1 Play: 1.h4 Gh6 2.h8=G Gh3 3.Gxh3 Comments: Changed promotion. |
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P. H. Torngren
Solution: Set: 1... Ga3 2.h8=Q/R Play: 1.h8=B Ga3 2.Sb6+ Kb8 3.Be5 Comments: Gs incidental. |
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K. Behrens
Solution: 1.g8=B 1... Kg2 2.Bd5+ Kg1 3.Gc5 1... Kg1 2.Bd5 h2 Gc5 Comments: |
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T. R. Dawson
Solution: 1.g4 1... Gd2 2.Qf3 Ga2 3.Bc3 1...Kf2 2.Be5 Ke1/Gd2 3.Bg3 |
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E. W. Bennett
Solution: Left: 1.Rh2 Rh1/Rc8 2.Bg1/Bc7 etc
Comments: |
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G. Dobbs
Solution: 1.Ge5 1... Kxa6 2.Rd5 b5 3.Rd6 1... Ka5 2.Kb7 Kb5 3.Rd5 Comments: G prevents b5 in second line, but is not used in the mate. |
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T. R. Dawson
Solution: 1.Bb8 1... Ge2 2.Kb5 Gc4/Ge4 3.dxc4/dxe4
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J. Buchwald
Solution: 1.Bf6 Kc4 2.Ge5 Kd4 3/Gc7 Comments: Discovered mate. |
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E.E.Westbury
Solution: 1.Kb3
Comment: Elegant model mates. Three variations, unspectacular. |
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Composer
Solution: 1. Comments: |