To read the solutions and comments hold down the left mouse key and run the cursor across the blank area.
5 men 3 types

A. H. Kniest
Solution: 1.Se5 Kh8 2.Gd5 Kg8 3.Sf7‡ Comments: Asymmetry, switchback. 

A. Kniest
Solution: 1.Kc3 Gb1/a2 2.Rb8/h2 Ka2/b1 3.Ra8/h1‡ Comments: Symmetry 

W. Kramer
Solution: set 1....Ge2 2.Gf1 Gg2 3.Gh3‡


W. E. Lester
Solution: 1.Gb2 unstalemating Kb8 2.Bb6 Ka8 3.Rc8‡ 

T. R. Dawson
Solution:
Comments: Last move P(x)h8=G. As published, with Gh8 at g7 for 1.Rh3, the position was illegal. 

T. R. Dawson
Solution:
Comments: Changed play. Irreversible Gmove in set play. Stranded G in actual play. 

G. Bernecker
Solution: 1.Pg3 Gb7 2.Gg4 Gd7 3.Gc8‡ Comments: Rudimentary 

H. Hultberg
Solution:
Comments: Changed promotion. 

H. Hultberg
Solution:
Comments: Underpromotion to avoid stalemate. 

J. Manskopf
Solution: 1.Bg7 Gh8 2.Ba1 Gb8 3.PxGb8=Q/R‡ Comments: B and G interchange. White shepherds G to required destination. 

Miss D. D'Sylva
Solution:
Comments: BG bystander in second mate. 

H. Hultberg
Solution: Set: 1... Ka8 2.g8=Q+ Ka7 3.Qb8‡
Comments: Why Gh5? 

H. Hultberg
Solution: Set 1... Gd8 2.cxd8=S Gc8/Gh6 3.Sf7‡


C. Eckherdt
Solution: 1.Ge8 1... e3 2.Ge2 g4 3.Gh5‡ 1... g4 2.Ge3 g3 3.Gh3‡ Comments: G over P routes. BG stranded. 

W. E. Lester
Solution: 1.Qc7 (waiting move) Gc6 2.dxc6 g2 3.Qb7‡ Comments: Incidental G. 

E & P. H. Torngren
Solution: 1.Ga7 Gb1/Gf3 2.Rb7 any 3.Gc7‡


H. Hultberg & P. H. Torngren (independently)
Solution: Set 1... Gh6 2.h8=B any 3.Bf6‡ Play: 1.Rg5 Gh6 2.h8=S any 3.Sg6‡ Comments: With Rg5 the set and actual play reverse. 

H. Hultberg
Solution: Set: 1... Ga7 2.b8=S‰ 1... Ka7 2.b8=Q+ Ka6 3.Qa8(etc)‡
Comments: G incidental 

T. R. Dawson
Solution: 1.Gf1 1... Kg1/Kh1 2.Gf4+ Kh2 3.Gf2‡ 1... h3 2.g3 h4/Kg1/Kh1 3.Gf4‡ Comments: Set Stalemate 

H. Hultberg
Solution: Set: 1... Gh6 2.h8=B Gh1 3.Be5‡ 1... Gb8 2.h8+Q/R‡
Comments: Change of promotion. 

T. R. Dawson
Solution: 1.Ge7 1... Kb8 2.Bc6 Ka7/c8 3.Bb7‡ 1... Ka7 2.Bc8 Kb8/a8 3.Bb7‡ Comments: Same White formation in all mates, BK position varies. 

O. Dankert
Solution: 1.Ba2 Gd8 2.Kf8 Gg8 3.Ke7‡ Comments: WK switchback, G over G mate.


H. Hultberg
Solution: Set: 1... Gh6 2.h8=G Gh2 3.Gc3‡ 1... Gc3 2.h8=Q/R‡
Comments: Changed mate. 

H. Hultberg
Solution: Set: 1... Gb8 2.cxb8=B Ga8/Gh5 3.Bf6‡ 1... Gh5/Gb5 2.c8=Q/R‡
Comments: Not cxb8=Q stalemate. 

P. H. Torngren
Solution: Set: 1...Gh6 2.h8=G Gh1 3.Gb8‡ 1... Gb8 2.h8=Q/R‡
Comments: 

T. R. Dawson
Solution: 1.Be7 1... Kb8 2.Bd6+ Ka7 3.Gd7‡ 1... Gd8/Gc5/Gd2 2.B(x)c5+ Kb8 3.Gb5‡ Comments: 

H. Hultberg
Solution: Set: 1... Gh6 2.h8=S Gf4/Gh3 3.Sg6‡ Play: 1.g6 Gh6 2.h8=B Gf6/Gh3 3.B(x)f6‡ Comments: Changed promotion. 

H. Hultberg
Solution: Set: 1... Gh6 2.h8=Q Gxh2 3.Qa1‡ Play: 1.h4 Gh6 2.h8=G Gh3 3.Gxh3‡ Comments: Changed promotion. 

P. H. Torngren
Solution: Set: 1... Ga3 2.h8=Q/R‡ Play: 1.h8=B Ga3 2.Sb6+ Kb8 3.Be5‡ Comments: Gs incidental. 

K. Behrens
Solution: 1.g8=B 1... Kg2 2.Bd5+ Kg1 3.Gc5‡ 1... Kg1 2.Bd5 h2 Gc5‡ Comments: 

T. R. Dawson
Solution: 1.g4 1... Gd2 2.Qf3 Ga2 3.Bc3‡ 1...Kf2 2.Be5 Ke1/Gd2 3.Bg3‡ 

E. W. Bennett
Solution: Left: 1.Rh2 Rh1/Rc8 2.Bg1/Bc7 etc ‡
Comments: 

G. Dobbs
Solution: 1.Ge5 1... Kxa6 2.Rd5 b5 3.Rd6‡ 1... Ka5 2.Kb7 Kb5 3.Rd5‡ Comments: G prevents b5 in second line, but is not used in the mate. 

T. R. Dawson
Solution: 1.Bb8 1... Ge2 2.Kb5 Gc4/Ge4 3.dxc4/dxe4 ‡


J. Buchwald
Solution: 1.Bf6 Kc4 2.Ge5 Kd4 3/Gc7‡ Comments: Discovered mate. 

E.E.Westbury
Solution: 1.Kb3
Comment: Elegant model mates. Three variations, unspectacular. 

Composer
Solution: 1. ‡ Comments: 