(solution C12 JulDec 1981 p.6)

Solution:1.Kf5 Kh4 2.Sg6† Kh5 3.Gf7‡ Comments: Asymmetry. 
(solution Jun 1976 p.270)

Solution:1.Re2 Gf1 2.Rg2 Gh3 3.Rg8 Bf6‡ and 1.Rb7 Bd8 2.Bg8 Gc8 3.Rh7 Bf6‡ double check mates. Comments: "Yes, this last move order is unique, and the try Rb7g7g8 Bf6 fails to Rg7 Many victims!" C.J.Feather. "Composer has happy knack for extracting play from slender force" J.E.Driver. Exact echo (reflection in diagonal a1h8). 
(solution Nov 1979 p.559)

Solution:1.Sf7 Kg4 2.Ke4 Kh5 3.Kf3 g4† 4.Kg3‡ Comments: Asymmetry. "Fairy pieces with simple construction is always attractive" V. R.. "Ideal mate difficult to visualise" D. A. Smedley. "Clever and difficult" V. A. C. "Almost gave up (some did!) but well worth the struggle" D. Nixon. 
(solution Chessics 8 Oct 1979 p.5)

Solution:1.Kg5 Sf1 2.Ge5 Sd2 3.Gh5 Gd1 4.Kh4 Sf3‡ Comments: Asymmetry. All pieces in one diagonal line. 

Solution:1.c4 Kc2 2.c3 Kd3 3.c2 Ke4 4.c1=B Kf5 5.Bb2 Kg6 6.Gb1 Gh8 7.Gh7 Ga1 8.Kh8 Kf7 9.Bd4 Kf8 10.Bg1 Gh1† 11.Bh2 Gh3‡
Comments: This problem was unsound, but could probably be saved with fewer moves. 
(solution issue 3 JanFeb 1988 p.37)

In an Equimover the pairs of moves are equal in length. Solution:(a) 1.Ge5 Gf1 2.Ge1 Gf5 3.Ge3 Gf3‡
Comments: "Severe move restrictions" D. Nixon. "Deux pas de deux" R. Brain. Same mate (apart from WK position).

(solution May 1979 p.328)

Solution: 1.Bb3 Bd2† 2.Kb2 Kb4 3.Ka1† Ka3 4.Gd3† Bc3‡ Comments: Asymmetry. Pinning piece cannot capture the pinned piece. 
(solution C12 JulDec 1981 p.6)

Solution: Add BKh3 for 1.Gf4 Kd3 2.Gh4 Kc2 3.Kg2 Kd1 4.Gh2 Ke1 5.Kh1 Kf1 6.Gf2† Bf3‡ Comments: The original setting had WKe4 and asked: add BK for HPM5 (add BKg3 for 1.Gh4 Ke3 2.Gdf4 Kd2 ...) but was unsound since Kd2 is selfcheck. Corrected 23 Oct 2012. Asymmetry. 