Out of 500 grasshopper chess problems I had collected by March 1976, using only grasshoppers and orthodox men, I had found only five that showed retroanalytical effects. Accordingly I set out to compose a set of Last Move problems in Grasshopper Chess. In these problems it is assumed that the Grasshoppers have appeared by promotion of pawns. This is in addition to the usual pawn promotion spectrum. If a position can be found using fewer pieces, this is usually considered an improvement in this type of composition. The problem is often to find a move that will allow a preceding move. It is important to notice checks, or unchecks as they are called looking backwards, and to take account of all possible uncaptures and unpromotions. | ||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
G. P. Jelliss Chessics #1, March 1976
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Solutions (given in Chessics #4, October 1977, together with corrected settings to six of the problems). Run the cursor over the space to see the solution. The sign ~ indicates a move or capture. 1. Kd1×Sc1, preceded by Sb3~c1+, 6 men. ||
2.f7-f8=G, not g7×f8=G since Gf6 has no move to give the check, 10 men. || |
3.Gd5×Gh1, preceded by Ge4~h1+, 11 men. ||
4.Sg2×Se1, preceded by Sf3~e1+, 12 men. || |
5.b2×Ga1=G, 13 men. ||
6.g2×Sh1=B, preceded by Sg3~h1+, 11 men. || | |
7.Gc1-a1, preceded by Ga1~c3, 12 men. ||
8.Rh8×Gg8, 10 men. || |
9.c7×Bb8=G, preceded by a5-a4, c6-c7, 15 men. ||
10.Ga7×Sc7, preceded by Sa6~c7++, 9 men. || |
11.Bf2×Sg2, 10 men. ||
12.f2×Sg1=G, preceded by Sg3×Xg1 (where X can be various pieces), 9 men. || |
13.Sf1×Ph2, preceded by h3-h2, so the last two moves are determined here, 15 men. ||
14.Sc8×Ra7, preceded by Rb7~a7+, 11 men. || |
15.Ke1×Gf1, 11 men. ||
16.Gf7×Bh7, preceded by Bg6~h7+, the man uncaptured cannot be P or Q since all 8 Black pawns are already accounted for (5P and 3G), 12 men. || |
17.e7×Qd8=G, 18 men. ||
18.a7×Gb8=B, 12 men. || |
19.Bh2-g1, 10 men. ||
20.Ba2×Gb1, 12 men. || |
21.b3×Sa4, 9 men. ||
22.Kg5-h6, preceded by h6-h7, 14 men. At the time I had not achieved a position showing PxB(B) and set this as a challenge, but no solution was received by October 1977, but was solved by issue #5, July 1978. Further notes to be added in due course. |